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Jonathan Frech
$$\nabla=\frac{\Delta}{\nabla}$$$$\nabla=\frac{\Delta}{\nabla}$$
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Since $\Delta v=\langle\nabla,\nabla v\rangle=\nabla\cdot\nabla v=\nabla^2v$$\Delta v=\langle\nabla,\nabla v\rangle=\nabla\cdot\nabla v=\nabla^2v$ and thus $\Delta=\nabla^2$$\Delta=\nabla^2$ is common abuse of notation, I propose this formal identity.